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The interval on which the function f(x) = 2x3 + 9x2 + 12x – 1 is decreasing is ______.

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प्रश्न

The interval on which the function f(x) = 2x3 + 9x2 + 12x – 1 is decreasing is ______.

विकल्प

  • `[–1, oo)`

  • [– 2, – 1]

  • `(-oo, -2]`

  • [– 1, 1]

MCQ
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उत्तर

The interval on which the function f(x) = 2x3 + 9x2 + 12x – 1 is decreasing is [– 2, – 1].

Explanation:

The given function is f(x) = 2x3 + 9x2 + 12x – 1

f'(x) = 6x2 + 18x + 12

For increasing and decreasing f'(x) = 0

∴ 6x2 + 18x + 12 = 0

⇒ x2 + 3x + 2 = 0

⇒ x2 + 2x + x + 2 = 0

⇒ x(x + 2) + 1(x + 2) = 0

⇒ (x + 2)(x + 1) = 0

⇒ x = – 2, x = – 1

The possible intervals are `(–oo, – 2), (– 2, – 1), (– 1, oo)`

Now f'(x) = (x + 2) (x + 1)

⇒ `"f'"(x)_((-oo"," -2))` = (–) (–) = (+) increasing

⇒ `"f'"(x)_((-2"," -1))` = (+) (–) = (–) decreasing

⇒ `"f'"(x)_((-1"," oo))` = (+) (+) = (+) increasing.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १४०]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 46 | पृष्ठ १४०

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