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Let F Defined on [0, 1] Be Twice Differentiable Such that | F"(X) | ≤ 1 for All X ∈ [0, 1]. If F(0) = F(1), Then Show that | F'(X) | < 1 for All X ∈ [ 0, 1] ?

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प्रश्न

Let f defined on [0, 1] be twice differentiable such that | f (x) | ≤ 1 for all x ∈ [0, 1]. If f(0) = f(1), then show that | f'(x) | < 1 for all x ∈ [ 0, 1] ?

योग
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उत्तर

If a function is continuous and differentiable and f(0) = f(1) in given domain x ∈ [0, 1],
then by Rolle's Theorem;
f'(x) = 0 for some x ∈ [0, 1]
Given: | f"(x)| ≤ 1
On integrating both sides we get,
|f'(x)| ≤ x
Now, within interval x ∈ [0, 1]
We get, | f' (x)| < 1.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३५]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 38 | पृष्ठ ३५

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