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Find the intervals in which the function f(x) = 3x4 − 4x3 − 12x2 + 5 is

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प्रश्न

Find the intervals in which the function f(x) = 3x4 − 4x3 − 12x2 + 5 is

(a) strictly increasing

(b) strictly decreasing

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उत्तर

We have:

`f(x) = 3x^4 − 4x^3 −12x^2 + 5`

`Now, f'(x) = 12x^3 − 12x^2 − 24x`

`Now, f'(x) = 0`

`⇒12x^3 −12x^2−24x = 0`

`⇒12x(x^2−x−2) = 0`

`⇒12x(x^2−2x+x−2)=0`

`⇒12x[x(x−2)+1(x−2)] = 0`

`⇒12x (x+1)(x−2)=0`

`⇒x=0 ; x = −1; x = 2`

So, the points x = −1, x = 0 and x = 2 divide the real line into four disjoint intervals, namely (,1), (1,0), (0,2) and (2,).

 INTERVAL SIGN OF f ' (x)=12x (x+1)(x −2)  NATURE OF FUNCTION
(,1) ()()()=or<0 Strictly decreasing
(1,0) ()(+)()=+or>0 Strictly increasing
(0,2) (+)(+)() =  or<0 Strictly decreasing
(2,) (+)(+)(+) = + or >0 Strictly increasing


(a) The given function is strictly increasing in the intervals (1,0)  (2,).
(b) The given function is strictly decreasing in the intervals (,1)  (0,2).

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