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The Function F(X) = −X/2 + Sin X Defined on [−π/3, π/3] is

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प्रश्न

The function f(x) = −x/2 + sin x defined on [−π/3, π/3] is

विकल्प

  • increasing

  • decreasing

  • constant

  • none of these

MCQ
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उत्तर

\[f(x) = \frac{- x}{2} + \sin x\text {  defined on } \left[ \frac{- \pi}{3}, \frac{\pi}{3} \right]\]

\[ \therefore f'(x) = \frac{- 1}{2} + \cos x \]

\[ \Rightarrow f'(x) \geqslant 0 \forall x \in \left[ \frac{- \pi}{3}, \frac{\pi}{3} \right]\]

\[\left[ \because \text { for } x \in \left[ \frac{- \pi}{3}, \frac{\pi}{3} \right] , \cos x \geqslant \frac{1}{2} \right]\]

Hence, the given function is increasing .

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Increasing and Decreasing Functions - Exercise 17.4 [पृष्ठ ४१]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.4 | Q 28 | पृष्ठ ४१

वीडियो ट्यूटोरियलVIEW ALL [3]

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