हिंदी

Without Using the Derivative, Show that the Function F (X) = | X | Is. (A) Strictly Increasing in (0, ∞) (B) Strictly Decreasing in (−∞, 0).

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प्रश्न

Without using the derivative, show that the function f (x) = | x | is.
(a) strictly increasing in (0, ∞)
(b) strictly decreasing in (−∞, 0) .

योग
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उत्तर

\[\text { Here }, \]

\[f\left( x \right) = \left| x \right|\]

\[(a) \text { Let } x_1 , x_2 \in \left( 0, \infty \right) \text { such that } x_1 < x_2 . \text { Then },\]

\[ x_1 < x_2 \]

\[ \Rightarrow \left| x_1 \right| < \left| x_2 \right|\]

\[ \Rightarrow f\left( x_1 \right) < f\left( x_2 \right)\]

\[\therefore x_1 < x_2 \Rightarrow f\left( x_1 \right) < f\left( x_2 \right), \forall x_1 , x_2 \in \left( 0, \infty \right)\]

\[\text { So },f\left( x \right) \text { is increasing on }\left( 0, \infty \right).\]

\[(b) \text { Let } x_1 , x_2 \in ( - \infty , 0]. \text { such that } x_1 < x_2 . \text { Then },\]

\[ x_1 < x_2 \]

\[ \Rightarrow \left| x_1 \right| > \left| x_2 \right|\]

\[ \Rightarrow f\left( x_1 \right) > f\left( x_2 \right)\]

\[\therefore x_1 < x_2 \Rightarrow f\left( x_1 \right) > f\left( x_2 \right), \forall x_1 , x_2 \in ( - \infty , 0].\]

\[\text { So },f\left( x \right) \text { is decreasing on }( - \infty , 0].\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Increasing and Decreasing Functions - Exercise 17.1 [पृष्ठ १०]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.1 | Q 8 | पृष्ठ १०

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