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Find the Interval in Which the Following Function Are Increasing Or Decreasing F(X) = X3 − 6x2 + 9x + 15 ?

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प्रश्न

Find the interval in which the following function are increasing or decreasing f(x) = x3 − 6x2 + 9x + 15 ?

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उत्तर

\[\text { When } \left( x - a \right)\left( x - b \right)>0 \text { with }a < b, x < a \text { or }x>b.\]

\[\text { When } \left( x - a \right)\left( x - b \right)<0 \text { with } a < b, a < x < b .\]

\[f\left( x \right) = x^3 - 6 x^2 + 9x + 15\]

\[f'\left( x \right) = 3 x^2 - 12x + 9\]

\[ = 3 \left( x^2 - 4x + 3 \right)\]

\[ = 3 \left( x - 1 \right)\left( x - 3 \right)\]

\[\text { For f(x) to be increasing, we must have }\]

\[f'\left( x \right) > 0\]

\[ \Rightarrow 3 \left( x - 1 \right)\left( x - 3 \right) > 0 \]

\[ \Rightarrow \left( x - 1 \right)\left( x - 3 \right) > 0 \left[ \text { Since } 3 > 0, 3 \left( x - 1 \right)\left( x - 3 \right) > 0 \Rightarrow \left( x - 1 \right)\left( x - 3 \right) > 0 \right]\]

\[ \Rightarrow x < 1 \ or \ x > 3\]

\[ \Rightarrow x \in \left( - \infty , 1 \right) \cup \left( 3, \infty \right)\]

\[\text { So,f(x)is increasing on } x \in \left( - \infty , 1 \right) \cup \left( 3, \infty \right).\]

\[\text { For f(x) to be decreasing, we must have }\]

\[f'\left( x \right) < 0\]

\[ \Rightarrow 3 \left( x - 1 \right)\left( x - 3 \right) < 0\]

\[ \Rightarrow \left( x - 1 \right)\left( x - 3 \right) < 0 \left[ \text { Since } 3 > 0, 3 \left( x - 1 \right)\left( x - 3 \right) < 0 \Rightarrow \left( x - 1 \right)\left( x - 3 \right) < 0 \right]\]

\[ \Rightarrow 1 < x < 3 \]

\[ \Rightarrow x \in \left( 1, 3 \right)\]

\[\text { So,f(x)is decreasing on x } \in \left( 1, 3 \right) .\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३३]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 16 Increasing and Decreasing Functions
Exercise 17.2 | Q 1.24 | पृष्ठ ३३

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