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Find the intervals in which the following functions are strictly increasing or decreasing: 6 − 9x − x2 - Mathematics

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प्रश्न

Find the intervals in which the following functions are strictly increasing or decreasing:

6 − 9x − x2

योग
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उत्तर

f(x) = 6 - 9x - x2

f'(x) = - 9x - 2x = -(2x + 9)

f'(x) = 0 ⇒ (2x + 9) = 0 ⇒ x = - `9/2`

The point x = `- 9/2` divides the number line into two parts, intervals `(- oo, - 9/2)` and `(- 9/2, oo)`.

In the interval `(- oo, - 9/2)`, f'(x) = (-)(-) = + Positive

Hence, the function f is continuously increasing.

In the interval `(- 9/2, oo)`, f'(x) = (-)(+) = - Negative

Hence, the function f is continuously decreasing.

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अध्याय 6: Application of Derivatives - Exercise 6.2 [पृष्ठ २०५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.2 | Q 6.4 | पृष्ठ २०५

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