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Find the Interval in Which the Following Function Are Increasing Or Decreasing F(X) = −2x3 − 9x2 − 12x + 1 ? - Mathematics

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प्रश्न

Find the interval in which the following function are increasing or decreasing f(x) = −2x3 − 9x2 − 12x + 1  ?

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उत्तर

\[\text { When } \left( x - a \right)\left( x - b \right)>0 \text { with }a < b, x < a \text { or }x>b.\]

\[\text { When } \left( x - a \right)\left( x - b \right)<0 \text { with } a < b, a < x < b .\]

\[f\left( x \right) = - 2 x^3 - 9 x^2 - 12x + 1\]

\[f'\left( x \right) = - 6 x^2 - 18x - 12\]

\[ = - 6 \left( x^2 + 3x + 2 \right)\]

\[ = - 6 \left( x + 1 \right)\left( x + 2 \right)\]

\[\text { For }f(x) \text { to be increasing, we must have }\]

\[f'\left( x \right) > 0\]

\[ \Rightarrow - 6 \left( x + 1 \right)\left( x + 2 \right) > 0\]

\[ \Rightarrow \left( x + 1 \right)\left( x + 2 \right) < 0 \left[ \text { Since  }- 6 < 0, - 6 \left( x + 1 \right)\left( x + 2 \right) > 0 \Rightarrow \left( x + 1 \right)\left( x + 2 \right) < 0 \right]\]

\[ \Rightarrow - 2 < x < - 1 \]

\[ \Rightarrow x \in \left( - 2, - 1 \right)\]

\[\text { So },f(x)\text { is increasing on } \left( - 2, - 1 \right) . \]

\[\text { For }f(x) \text { to be decreasing, we must have }\]

\[f'\left( x \right) < 0\]

\[ \Rightarrow - 6 \left( x + 1 \right)\left( x + 2 \right) < 0\]

\[ \Rightarrow \left( x + 1 \right)\left( x + 2 \right) > 0 \left[ \text { Since } - 6 < 0, - 6 \left( x + 1 \right)\left( x + 2 \right) < 0 \Rightarrow \left( x + 1 \right)\left( x + 2 \right) > 0 \right]\]

\[ \Rightarrow x < - 2 \ or \ x > - 1 \]

\[ \Rightarrow x \in \left( - \infty , - 2 \right) \cup \left( - 1, \infty \right)\]

\[\text { So,}f(x)\text { is decreasing on } \left( - \infty , - 2 \right) \cup \left( - 1, \infty \right) .\]

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अध्याय 17: Increasing and Decreasing Functions - Exercise 17.2 [पृष्ठ ३३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 17 Increasing and Decreasing Functions
Exercise 17.2 | Q 1.14 | पृष्ठ ३३

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