हिंदी

Show that for a ≥ 1, f(x) = 3 sinx – cosx – 2ax + b ∈ is decreasing in R

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प्रश्न

Show that for a ≥ 1, f(x) = `sqrt(3)` sinx – cosx – 2ax + b ∈ is decreasing in R

योग
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उत्तर

Given that: f(x) = `sqrt(3)` sinx – cosx – 2ax + b, a ≥ 1

Differentiating both sides w.r.t. x, we get

f'(x) = `sqrt(3) cos x + sin x - 2"a"`

For decreasing function, f'(x) < 0

∴ `sqrt(3) cos x + sin x - 2"a" < 0`

⇒ `2(sqrt(3)/2 cos x + 1/2 sin x) - 2"a" < 0`

⇒ `sqrt(3)/2 cos x + 1/2 sin x - "a" < 0`

⇒ `(cos  pi/6 cos x + sin  pi/6 sin x) - "a" < 0`

⇒ `cos(x - pi/6) - "a " < 0`

Since cos x ∈ [– 1, 1] and a ≥ 1

∴ f'(x) < 0

Hence, the given function is decreasing in R.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १३७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 21 | पृष्ठ १३७

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