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The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample. - Chemistry

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प्रश्न

The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.

संख्यात्मक
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उत्तर

Radioactive decay follows first order kinetics. 

 ∴ Decay constant (λ) = `0.693/t_(1//2)`

= `0.693/5730` year−1

Given, [R]= 100

∴ [R] = 80

t = `2.303/λ log  [R]_0/[R]`

= `2.303/((0.693/5730)) log  100/80`

= `(2.303 xx 5730)/0.693 xx 0.0969` year

= 1845 years

Hence, the age of the sample is 1845 years.

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अध्याय 3: Chemical Kinetics - Exercises [पृष्ठ ८६]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 3 Chemical Kinetics
Exercises | Q 3.14 | पृष्ठ ८६

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