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प्रश्न
After 2 hours, a radioactive substance becomes `(1/16)^"th"` of original amount. Then the half life ( in min) is
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उत्तर
30 minutes
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संबंधित प्रश्न
The integrated rate equation for first order reaction is A → products
A first order reaction takes 40 minutes for 30% decomposition. Calculate t1/2 for this reaction. (Given log 1.428 = 0.1548)
The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
Which among the following reactions is an example of a zero order reaction?
a) `H_(2(g)) + I_(2(g)) -> 2HI_(g)`
b) `2H_2O_(2(l)) -> 2H_2O_(l) + O_(2(g))`
c) `C_12H_22O_(11(aq)) + H_2O_(l) -> C_6H_12O_(6(aq)) + C_6H_12O_(6(aq))`
d) `2NH_(3g)` `N(2g) + 3H_(2(g))`
Half life (t1/2) and completion time (T) of the zero order reaction are- (K = 0.001 mol/litre/sec and a = 1 M.)
Observe the graph shown in figure and answer the following questions:
Write the relationship between k and t1/2 (half-life period)
The amount of C-14 isotope in a piece of wood is found to be 1/16th of its amount present in a fresh piece of wood. The age of wood, half-life period of C-14 is 5770 years, is ______ years.
For the given first order reaction A → B the half life of the reaction is 0.3010 min. The ratio of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to ______. (Nearest integer)
Show that the half-life of zero order reaction is `t_(1/2) = ([A]_0)/(2k)`.
Calculate the half-life of a first order reaction from the rate constant given below:
2 min−1
