Advertisements
Advertisements
प्रश्न
A first-order reaction takes 69.3 min for 50% completion. What is the time needed for 80% of the reaction to get completed? (Given: log 5 = 0.6990, log 8 = 0.9030, log 2 = 0.3010)
Advertisements
उत्तर
Half-life `t_(1/2) = 0.693/k`
k = `0.693/69.3 = 1/100` = 0.01 min–1
For first-order reaction
k = `2.303/t log ([Ro])/([R])`
t = `2.303/0.01 log 100/20`
t = 230.3 log 5 (log 5 = 0.6990)
t = 160.9 min
APPEARS IN
संबंधित प्रश्न
Derive the relation between half life and rate constant for a first order reaction
The half-life for radioactive decay of 14C is 5730 years. An archaeological artifact containing wood had only 80% of the 14C found in a living tree. Estimate the age of the sample.
The rate constant for the first order decomposition of H2O2 is given by the following equation:
log k = 14.34 − 1.25 × 104 K/T
Calculate Ea for this reaction and at what temperature will its half-period be 256 minutes?
The half-life period of zero order reaction A → product is given by
(a) `([A]_0)/k`
(b) `0.693/k`
(c) `[A]_0/(2k)`
(d) `(2[A]_0)/k`
The half life period of a first order reaction is 6. 0 h . Calculate the rate constant
The half life period of a radioactive element is 140 days. After 560 days, 1 g of element will be reduced to
Calculate half-life period of life order reaction whose rate constant is 200 sec–1
Observe the graph shown in figure and answer the following questions:
Write the relationship between k and t1/2 (half-life period)
The amount of C-14 isotope in a piece of wood is found to be 1/16th of its amount present in a fresh piece of wood. The age of wood, half-life period of C-14 is 5770 years, is ______ years.
For the given first order reaction A → B the half life of the reaction is 0.3010 min. The ratio of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to ______. (Nearest integer)
