हिंदी

Which radioactive isotope would have the longer half-life 15O or 19O? (Given rate constants for 15O and 19O are 5.63 × 10–3s–1 and k = 2.38 × 10–2s–1 respectively.) - Chemistry

Advertisements
Advertisements

प्रश्न

Which radioactive isotope would have the longer half-life 15O or 19O? (Given rate constants for 15O and 19O are 5.63 × 10–3 s–1 and k = 2.38 × 10–2 s–1 respectively.)

विकल्प

  • 15

  • 19O

  • Both will have the same half-life

  • None of the above, information given is insufficient

MCQ
Advertisements

उत्तर

15

Explanation:

The rate constant for the decay of 15O is less than that for 19O. Therefore, the rate of decay of 15O will be slower and will have a longer half-life. 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Sample

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

The integrated rate equation for first order reaction is A → products


Derive the relation between half life and rate constant for a first order reaction


A first order reaction takes 23.1 minutes for 50% completion. Calculate the time required for 75% completion of this reaction.

(log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)


A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.

(log 2 = 0.3010)


The experimental data for decomposition of N2O5.

\[\ce{2N2O5 -> 4NO2 + O2}\] in gas phase at 318 K are given below:

t/s 0 400 800 1200 1600 2000 2400 2800 3200
102 × [N2O5]/mol L−1 1.63 1.36 1.14 0.93 0.78 0.64 0.53 0.43 0.35
  1. Plot [N2O5] against t.
  2. Find the half-life period for the reaction.
  3. Draw a graph between log [N2O5] and t.
  4. What is the rate law?
  5. Calculate the rate constant.
  6. Calculate the half-life period from k and compare it with (ii).

A first order reaction takes 10 minutes for 25% decomposition. Calculate t1/2 for the reaction.

(Given : log 2 = 0.3010, log 3 = 0.4771, log 4 = 0.6021)


Calculate half-life period of life order reaction whose rate constant is 200 sec–1


The amount of C-14 isotope in a piece of wood is found to be 1/16th of its amount present in a fresh piece of wood. The age of wood, half-life period of C-14 is 5770 years, is ______ years.


The rate of a first order reaction is 0.04 mol litre-1 s-1 at 10 minutes and 0.03 mol litre-1 sec-1 at 20 minutes after initiation. The half-life of the reaction is ______ min.


A first order reaction takes 40 min for 30% decomposition. Calculate `"t"_(1/2)`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×