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प्रश्न
The formation of the depletion region in a p-n junction diode is due to ______.
विकल्प
movement of dopant atoms
diffusion of both electrons and holes
drift of electrons only
the drift of holes only
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उत्तर
The formation of the depletion region in a p-n junction diode is due to the diffusion of both electrons and holes.
Explanation:
Charge diffusion is what creates the depletion area. holes diffuse across the junction from the p-side to the n-side due to the concentration gradient, whereas electrons diffuse from the n-side to the p-side. Near the junction, the holes and the electrons that are diffusely moving in the same direction unite.
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संबंधित प्रश्न
A zener diode is fabricated by heavily doping both p- and n- sides of the junction. Explain, why?
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If the two ends of a p-n junction are joined by a wire,
When a p-n junction is reverse-biased, the current becomes almost constant at 25 µA. When it is forward-biased at 200 mV, a current of 75 µA is obtained. Find the magnitude of diffusion current when the diode is
(a) unbiased,
(b) reverse-biased at 200 mV and
(c) forward-biased at 200 mV.
The current−voltage characteristic of an ideal p-n junction diode is given by \[i = i_0 ( e^{eV/KT} - 1)\] where, the drift current i0 equals 10 µA. Take the temperature T to be 300 K. (a) Find the voltage V0 for which \[e^{eV/kT} = 100 .\]One can neglect the term 1 for voltages greater than this value. (b) Find an expression for the dynamic resistance of the diode as a function of V for V > V0. (c) Find the voltage for which the dynamic resistance is 0.2 Ω.
(Use Planck constant h = 4.14 × 10-15 eV-s, Boltzmann constant k = 8·62 × 10-5 eV/K.)
Draw the current-voltage characteristics for the device show in figure between the terminals A and B.
(Assume that the resistance of each diode is zero in forward bias and is infinity in reverse bias.)
Choose the correct option.
Current through a reverse-biased p-n junction increases abruptly at:
p-n junction diode is formed
