Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π - Mathematics

Solve 2 tan²x + sec²x = 2 for 0 ≤ x ≤ 2π.

योग

Here, 2 tan²x + sec²x = 2

Which gives tan x = `+- 1/sqrt(3)`

If we take tan x = `1/sqrt(3)`

Then x = `pi/6` or `(7pi)/6`

Again, if we take tan x = `(-1)/sqrt(3)`

Then x = `(5pi)/6` or `(11pi)/6`

Therefore, the possible solutions to the above equations are

x = `pi/6, (5pi)/6, (7pi)/6` and `(11pi)/6` where 0 ≤ x ≤ 2π.

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अध्याय 3: Trigonometric Functions - Solved Examples [पृष्ठ ४२]

अध्याय 3 Trigonometric Functions
Solved Examples | Q 8 | पृष्ठ ४२

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