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Solve 3 cos θ + sin θ = 2

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प्रश्न

Solve `sqrt(3)` cos θ + sin θ = `sqrt(2)`

योग
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उत्तर

Divide the given equation by 2 to get

`sqrt(3)/2 cos theta + 1/2 sin theta = 1/sqrt(2)`

or `cos  pi/6 cos theta + sin  pi/6 sin theta = cos  pi/4`

or `cos(pi/6 - theta) = cos  pi/4` or `cos(theta - pi/6) = cos  pi/4` 

Thus, the solution is given by, i.e., θ = `2 m pi +- pi/4 + pi/6`

Hence, the solution is

θ = `2 m pi + pi/4 + pi/6` and `2 m pi - pi/4 + pi/6,` i.e., `theta = 2 m pi + (5pi)/12` and `theta = 2 m pi - pi / 12`

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अध्याय 3: Trigonometric Functions - Solved Examples [पृष्ठ ४७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 3 Trigonometric Functions
Solved Examples | Q 14 | पृष्ठ ४७

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