Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
If cos pθ + cos qθ = 0 and if p ≠ q, then θ is equal to (n is any integer)
विकल्प
`(pi(3"n" + 1))/("p" - "q")`
`(pi(2"n" + 1))/("p" +- "q")`
`(pi("n" +- 1))/("p" +- "q")`
`(pi("n" + 2))/("p" + "q")`
Advertisements
उत्तर
`(pi(2"n" + 1))/("p" +- "q"`
APPEARS IN
संबंधित प्रश्न
Find the general solution of the equation sin x + sin 3x + sin 5x = 0
If \[\tan x = \frac{b}{a}\] , then find the values of \[\sqrt{\frac{a + b}{a - b}} + \sqrt{\frac{a - b}{a + b}}\].
If \[\tan x = \frac{a}{b},\] show that
If \[T_n = \sin^n x + \cos^n x\], prove that \[6 T_{10} - 15 T_8 + 10 T_6 - 1 = 0\]
Prove that: tan (−225°) cot (−405°) −tan (−765°) cot (675°) = 0
If tan x = \[x - \frac{1}{4x}\], then sec x − tan x is equal to
If tan x + sec x = \[\sqrt{3}\], 0 < x < π, then x is equal to
The value of \[\cos1^\circ \cos2^\circ \cos3^\circ . . . \cos179^\circ\] is
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
\[\sec x\cos5x + 1 = 0, 0 < x < \frac{\pi}{2}\]
If \[2 \sin^2 x = 3\cos x\]. where \[0 \leq x \leq 2\pi\], then find the value of x.
If \[\cos x + \sqrt{3} \sin x = 2,\text{ then }x =\]
The number of solution in [0, π/2] of the equation \[\cos 3x \tan 5x = \sin 7x\] is
If \[4 \sin^2 x = 1\], then the values of x are
If \[e^{\sin x} - e^{- \sin x} - 4 = 0\], then x =
Solve the following equations:
2 cos2θ + 3 sin θ – 3 = θ
Solve the following equations:
cot θ + cosec θ = `sqrt(3)`
If 2sin2θ = 3cosθ, where 0 ≤ θ ≤ 2π, then find the value of θ.
