हिंदी

If 4 Sin 2 X = 1 , Then the Values of X Are

Advertisements
Advertisements

प्रश्न

If \[4 \sin^2 x = 1\], then the values of x are

 

विकल्प

  • \[2 n\pi \pm \frac{\pi}{3}, n \in Z\]

  • \[n\pi \pm \frac{\pi}{3}, n \in Z\]

     

  • \[n\pi \pm \frac{\pi}{6}, n \in Z\]

  • \[2 n\pi \pm \frac{\pi}{6}, n \in Z\]
MCQ
योग
Advertisements

उत्तर

\[2 n\pi \pm \frac{\pi}{6}, n \in Z\]
Given:
\[4 \sin^2 x = 1\]
\[ \Rightarrow \sin^2 x = \frac{1}{4}\]
\[ \Rightarrow \sin x = \frac{1}{2}\text{ or }\sin x = - \frac{1}{2}\]
\[ \Rightarrow \sin x = \sin \frac{\pi}{6}\text{ or }\sin x = \sin \left( - \frac{\pi}{6} \right)\]
\[ \Rightarrow x = n\pi + ( - 1 )^n \frac{\pi}{6}, n \in Z\text{ or }x = n\pi + ( - 1 )^n \left( - \frac{\pi}{6} \right), n \in Z\]
\[ \Rightarrow x = n\pi \pm \frac{\pi}{6}, n \in Z\]
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Trigonometric equations - Exercise 11.3 [पृष्ठ २७]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 11 Trigonometric equations
Exercise 11.3 | Q 10 | पृष्ठ २७

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the principal and general solutions of the equation `tan x = sqrt3`


Find the principal and general solutions of the equation  `cot x = -sqrt3`


If \[T_n = \sin^n x + \cos^n x\], prove that \[\frac{T_3 - T_5}{T_1} = \frac{T_5 - T_7}{T_3}\]

 


Prove that:
\[\frac{\cos (2\pi + x) cosec (2\pi + x) \tan (\pi/2 + x)}{\sec(\pi/2 + x)\cos x \cot(\pi + x)} = 1\]

 


Find x from the following equations:
\[x \cot\left( \frac{\pi}{2} + \theta \right) + \tan\left( \frac{\pi}{2} + \theta \right)\sin \theta + cosec\left( \frac{\pi}{2} + \theta \right) = 0\]


Prove that:
\[\tan 4\pi - \cos\frac{3\pi}{2} - \sin\frac{5\pi}{6}\cos\frac{2\pi}{3} = \frac{1}{4}\]


If tan x = \[x - \frac{1}{4x}\], then sec x − tan x is equal to


If \[0 < x < \frac{\pi}{2}\], and if \[\frac{y + 1}{1 - y} = \sqrt{\frac{1 + \sin x}{1 - \sin x}}\], then y is equal to


If \[\frac{\pi}{2} < x < \pi, \text{ then }\sqrt{\frac{1 - \sin x}{1 + \sin x}} + \sqrt{\frac{1 + \sin x}{1 - \sin x}}\] is equal to


If tan \[x = - \frac{1}{\sqrt{5}}\] and θ lies in the IV quadrant, then the value of cos x is

 

sin6 A + cos6 A + 3 sin2 A cos2 A =


If \[cosec x - \cot x = \frac{1}{2}, 0 < x < \frac{\pi}{2},\]

 

\[\sec^2 x = \frac{4xy}{(x + y )^2}\] is true if and only if

 


If \[cosec x + \cot x = \frac{11}{2}\], then tan x =

 


If tan θ + sec θ =ex, then cos θ equals


If sec x + tan x = k, cos x =


Find the general solution of the following equation:

\[\sec x = \sqrt{2}\]

Find the general solution of the following equation:

\[\cos 3x = \frac{1}{2}\]

Find the general solution of the following equation:

\[\tan x + \cot 2x = 0\]

Find the general solution of the following equation:

\[\tan px = \cot qx\]

 


Solve the following equation:

\[\tan x + \tan 2x + \tan 3x = 0\]

Solve the following equation:

\[\sin x + \cos x = 1\]

Solve the following equation:
4sinx cosx + 2 sin x + 2 cosx + 1 = 0 


If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x.


Write the number of values of x in [0, 2π] that satisfy the equation \[\sin x - \cos x = \frac{1}{4}\].


If \[\tan px - \tan qx = 0\], then the values of θ form a series in

 


If a is any real number, the number of roots of \[\cot x - \tan x = a\] in the first quadrant is (are).


The number of solution in [0, π/2] of the equation \[\cos 3x \tan 5x = \sin 7x\] is 


The general value of x satisfying the equation
\[\sqrt{3} \sin x + \cos x = \sqrt{3}\]


Find the principal solution and general solution of the following:
cot θ = `sqrt(3)`


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

sin4x = sin2x


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

cos 2x = 1 − 3 sin x


Solve the following equations:
sin 2θ – cos 2θ – sin θ + cos θ = θ


Solve the following equations:
sin θ + cos θ = `sqrt(2)`


Solve the following equations:
cot θ + cosec θ = `sqrt(3)`


Solve `sqrt(3)` cos θ + sin θ = `sqrt(2)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×