हिंदी

Find the General Solution of the Following Equation: Tan 3 X = Cot X

Advertisements
Advertisements

प्रश्न

Find the general solution of the following equation:

\[\tan 3x = \cot x\]
योग
Advertisements

उत्तर

We have:

\[\tan3x = \cot x\]

\[\Rightarrow \tan3x = \tan \left( \frac{\pi}{2} - x \right)\]

\[ \Rightarrow 3x = n\pi + \left( \frac{\pi}{2} - x \right), n \in Z\]

\[ \Rightarrow 4x = n\pi + \frac{\pi}{2}, n \in Z\]

\[ \Rightarrow x = \frac{n\pi}{4} + \frac{\pi}{8}, n \in Z\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Trigonometric equations - Exercise 11.1 [पृष्ठ २१]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 11 Trigonometric equations
Exercise 11.1 | Q 2.06 | पृष्ठ २१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the general solution of cosec x = –2


If \[x = \frac{2 \sin x}{1 + \cos x + \sin x}\], then prove that

\[\frac{1 - \cos x + \sin x}{1 + \sin x}\] is also equal to a.

If \[T_n = \sin^n x + \cos^n x\], prove that \[6 T_{10} - 15 T_8 + 10 T_6 - 1 = 0\]


Prove that:  tan 225° cot 405° + tan 765° cot 675° = 0


Prove that: \[\tan\frac{11\pi}{3} - 2\sin\frac{4\pi}{6} - \frac{3}{4} {cosec}^2 \frac{\pi}{4} + 4 \cos^2 \frac{17\pi}{6} = \frac{3 - 4\sqrt{3}}{2}\]

 


Prove that:
\[\frac{\cos (2\pi + x) cosec (2\pi + x) \tan (\pi/2 + x)}{\sec(\pi/2 + x)\cos x \cot(\pi + x)} = 1\]

 


In a ∆ABC, prove that:

\[\tan\frac{A + B}{2} = \cot\frac{C}{2}\]

Find x from the following equations:
\[cosec\left( \frac{\pi}{2} + \theta \right) + x \cos \theta \cot\left( \frac{\pi}{2} + \theta \right) = \sin\left( \frac{\pi}{2} + \theta \right)\]


Prove that:
\[\sin\frac{13\pi}{3}\sin\frac{8\pi}{3} + \cos\frac{2\pi}{3}\sin\frac{5\pi}{6} = \frac{1}{2}\]


Prove that:

\[\tan\frac{5\pi}{4}\cot\frac{9\pi}{4} + \tan\frac{17\pi}{4}\cot\frac{15\pi}{4} = 0\]

 


If \[\frac{\pi}{2} < x < \pi, \text{ then }\sqrt{\frac{1 - \sin x}{1 + \sin x}} + \sqrt{\frac{1 + \sin x}{1 - \sin x}}\] is equal to


If x = r sin θ cos ϕ, y = r sin θ sin ϕ and r cos θ, then x2 + y2 + z2 is independent of


If tan x + sec x = \[\sqrt{3}\], 0 < x < π, then x is equal to


If \[cosec x + \cot x = \frac{11}{2}\], then tan x =

 


If tan θ + sec θ =ex, then cos θ equals


The value of \[\cos1^\circ \cos2^\circ \cos3^\circ . . . \cos179^\circ\] is

 

Which of the following is correct?


Find the general solution of the following equation:

\[\cos 3x = \frac{1}{2}\]

Solve the following equation:

\[\tan^2 x + \left( 1 - \sqrt{3} \right) \tan x - \sqrt{3} = 0\]

Solve the following equation:

\[\cos x + \cos 3x - \cos 2x = 0\]

Solve the following equation:

\[\sin x + \sin 2x + \sin 3 = 0\]

Solve the following equation:

\[\tan x + \tan 2x + \tan 3x = 0\]

Solve the following equation:
 cosx + sin x = cos 2x + sin 2x

 


Solve the following equation:
3tanx + cot x = 5 cosec x


Solve the following equation:
3 – 2 cos x – 4 sin x – cos 2x + sin 2x = 0


If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x.


Write the general solutions of tan2 2x = 1.

 

If \[e^{\sin x} - e^{- \sin x} - 4 = 0\], then x =


If \[\cos x = - \frac{1}{2}\] and 0 < x < 2\pi, then the solutions are


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 cos2x + 1 = – 3 cos x


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

2 sin2x + 1 = 3 sin x


Solve the following equations:
cos θ + cos 3θ = 2 cos 2θ


Choose the correct alternative:
If cos pθ + cos qθ = 0 and if p ≠ q, then θ is equal to (n is any integer)


Choose the correct alternative:
If tan α and tan β are the roots of x2 + ax + b = 0 then `(sin(alpha + beta))/(sin alpha sin beta)` is equal to


If 2sin2θ = 3cosθ, where 0 ≤ θ ≤ 2π, then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×