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Write the Number of Points of Intersection of the Curves 2 Y = − 1 and Y = C O S E C X

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प्रश्न

Write the number of points of intersection of the curves

\[2y = - 1 \text{ and }y = cosec x\]
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उत्तर

Given: 

2y = -1 and y= cosec x
Now,
2y = -1`=>`y = -`1/2`

\[cosecx = y\]

\[ \Rightarrow cosecx = - \frac{1}{2}\]

\[ \Rightarrow \frac{1}{\sin x} = - \frac{1}{2}\]

\[ \Rightarrow \sin x = - 2\]
The value of sine function lies between - 1 and 1. Therefore, the two curves will not intersect at any point.

Hence, the number of points of intersection of the curves is 0.

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अध्याय 11: Trigonometric equations - Exercise 11.2 [पृष्ठ २६]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 11 Trigonometric equations
Exercise 11.2 | Q 8 | पृष्ठ २६

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