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Find the general solution of the equation 5cos2θ + 7sin2θ – 6 = 0

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प्रश्न

Find the general solution of the equation 5cos2θ + 7sin2θ – 6 = 0

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उत्तर

5cos2θ + 7sin2θ – 6 = 0

We know that,

sin2θ = 1 – cos2θ

Therefore, 5cos2θ + 7(1 – cos2θ) – 6 = 0

⇒ 5cos2θ + 7 – 7cos2θ – 6 = 0

⇒ –2cos2θ + 1 = 0

⇒ cos2θ = `1/2`

Therefore, cosθ = `+- 1/sqrt(2)`

Therefore, cosθ = `cos  pi/4` or cosθ = `cos  (3pi)/4`

Since, the solution of cosx = cosα is given by,

x = 2mπ ± α ∀ m ∈ Z

θ = nπ ± `pi/4`, n ∈ Z

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अध्याय 3: Trigonometric Functions - Exercise [पृष्ठ ५५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise | Q 27 | पृष्ठ ५५

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