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The Smallest Value of X Satisfying the Equation √ 3 ( Cot X + Tan X ) = 4 is - Mathematics

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प्रश्न

The smallest value of x satisfying the equation

\[\sqrt{3} \left( \cot x + \tan x \right) = 4\] is 

विकल्प

  • \[2\pi/3\]

     

  • `pi/3`

  • `pi/6`

  • `pi/12`

MCQ
योग
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उत्तर

\[\pi/6\]
Given:

\[\sqrt{3}(\cot x + \tan x) = 4\]

\[ \Rightarrow \sqrt{3} \left( \frac{\cos x}{\sin x} + \frac{\sin x}{\cos x} \right) = 4\]

\[ \Rightarrow \sqrt{3} ( \cos^2 x + \sin^2 x) = 4 \sin x \cos x\]

\[ \Rightarrow \sqrt{3} = 2 \sin2x [\sin2x = 2 \sin x \cos x]\]

\[ \Rightarrow \sin2x = \frac{\sqrt{3}}{2}\]

\[ \Rightarrow \sin2x = \sin \frac{\pi}{3}\]

\[ \Rightarrow 2x = n\pi + ( - 1 )^n \frac{\pi}{3}, n \in Z\]

\[ \Rightarrow x = \frac{n\pi}{2} + ( - 1 )^n \frac{\pi}{6}, n \in Z\]
To obtain the smallest value of x, we will put n = 0 in the above equation.
Thus, we have:
`x=pi/6`
Hence, the smallest value of x is 
`pi/6`.

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अध्याय 11: Trigonometric equations - Exercise 11.3 [पृष्ठ २६]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 11 Trigonometric equations
Exercise 11.3 | Q 1 | पृष्ठ २६

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