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प्रश्न
The smallest value of x satisfying the equation
पर्याय
- \[2\pi/3\]
`pi/3`
`pi/6`
`pi/12`
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उत्तर
Given:
\[\sqrt{3}(\cot x + \tan x) = 4\]
\[ \Rightarrow \sqrt{3} \left( \frac{\cos x}{\sin x} + \frac{\sin x}{\cos x} \right) = 4\]
\[ \Rightarrow \sqrt{3} ( \cos^2 x + \sin^2 x) = 4 \sin x \cos x\]
\[ \Rightarrow \sqrt{3} = 2 \sin2x [\sin2x = 2 \sin x \cos x]\]
\[ \Rightarrow \sin2x = \frac{\sqrt{3}}{2}\]
\[ \Rightarrow \sin2x = \sin \frac{\pi}{3}\]
\[ \Rightarrow 2x = n\pi + ( - 1 )^n \frac{\pi}{3}, n \in Z\]
\[ \Rightarrow x = \frac{n\pi}{2} + ( - 1 )^n \frac{\pi}{6}, n \in Z\]
To obtain the smallest value of x, we will put n = 0 in the above equation.
Thus, we have:
`x=pi/6`
Hence, the smallest value of x is
`pi/6`.
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