हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Choose the correct alternative:If sin α + cos α = b, then sin 2α is equal to

Advertisements
Advertisements

प्रश्न

Choose the correct alternative:
If sin α + cos α = b, then sin 2α is equal to

विकल्प

  • b2 − 1, if `"b" ≤ sqrt(2)`

  • b2 − 1, if `"b" > sqrt(2)`

  • b2 − 1, if b ≥ 1

  • b2 − 1, if `"b" ≥ sqrt(2)`

MCQ
Advertisements

उत्तर

b2 − 1, if `"b" ≤ sqrt(2)`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.12 [पृष्ठ १५१]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.12 | Q 19 | पृष्ठ १५१

संबंधित प्रश्न

Find the principal and general solutions of the equation sec x = 2


Find the general solution of the equation  sin x + sin 3x + sin 5x = 0


Prove that: \[\tan\frac{11\pi}{3} - 2\sin\frac{4\pi}{6} - \frac{3}{4} {cosec}^2 \frac{\pi}{4} + 4 \cos^2 \frac{17\pi}{6} = \frac{3 - 4\sqrt{3}}{2}\]

 


Prove that:

\[3\sin\frac{\pi}{6}\sec\frac{\pi}{3} - 4\sin\frac{5\pi}{6}\cot\frac{\pi}{4} = 1\]

 


Prove that

\[\frac{cosec(90^\circ + x) + \cot(450^\circ + x)}{cosec(90^\circ - x) + \tan(180^\circ - x)} + \frac{\tan(180^\circ + x) + \sec(180^\circ - x)}{\tan(360^\circ + x) - \sec( - x)} = 2\]

 


Prove that:
\[\sin^2 \frac{\pi}{18} + \sin^2 \frac{\pi}{9} + \sin^2 \frac{7\pi}{18} + \sin^2 \frac{4\pi}{9} = 2\]

 

If tan x = \[x - \frac{1}{4x}\], then sec x − tan x is equal to


If \[\frac{3\pi}{4} < \alpha < \pi, \text{ then }\sqrt{2\cot \alpha + \frac{1}{\sin^2 \alpha}}\] is equal to


If \[cosec x + \cot x = \frac{11}{2}\], then tan x =

 


If x is an acute angle and \[\tan x = \frac{1}{\sqrt{7}}\], then the value of \[\frac{{cosec}^2 x - \sec^2 x}{{cosec}^2 x + \sec^2 x}\] is


Find the general solution of the following equation:

\[\sin x = \frac{1}{2}\]

Find the general solution of the following equation:

\[\cos x = - \frac{\sqrt{3}}{2}\]

Solve the following equation:
\[\cot x + \tan x = 2\]

 


If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x.


Write the general solutions of tan2 2x = 1.

 

Write the set of values of a for which the equation

\[\sqrt{3} \sin x - \cos x = a\] has no solution.

If \[3\tan\left( x - 15^\circ \right) = \tan\left( x + 15^\circ \right)\] \[0 < x < 90^\circ\], find θ.


The solution of the equation \[\cos^2 x + \sin x + 1 = 0\] lies in the interval


Solve `sqrt(3)` cos θ + sin θ = `sqrt(2)`


The minimum value of 3cosx + 4sinx + 8 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×