Advertisements
Advertisements
प्रश्न
If \[cosec x - \cot x = \frac{1}{2}, 0 < x < \frac{\pi}{2},\]
विकल्प
- \[\frac{5}{3}\]
- \[\frac{3}{5}\]
- \[- \frac{3}{5}\]
- \[- \frac{5}{3}\]
Advertisements
उत्तर
We have:
\[\text{ cosec }x - \cot x = \frac{1}{2} \left( 1 \right)\]
\[ \Rightarrow \frac{1}{\text{ cosec }x - \cot x} = 2\]
\[ \Rightarrow \frac{{\text{ cosec }}^2 x - \cot^2 x}{\text{ cosec }x - \cot x} = 2\]
\[ \Rightarrow \frac{\left(\text{ cosec }x + \cot x \right)\left( \text{ cosec }x - \cot x \right)}{\left(\text{ cosec }x - \cot x \right)} = 2\]
\[ \therefore\text{ cosec }x +\cot x = 2 \left( 2 \right)\]
Adding ( 1 ) and ( 2 ):
\[2\text{ cosec} x = \frac{1}{2} + 2\]
\[ \Rightarrow 2 \text{ cosec} x = \frac{5}{2}\]
\[ \Rightarrow\text{ cosec} x = \frac{5}{4}\]
\[ \Rightarrow \frac{1}{\sin x}=\frac{5}{4}\]
\[ \Rightarrow \sin x=\frac{4}{5}\]
\[\text{ Now, }0 < \theta < \frac{\pi}{2}\]
\[ \therefore \cos\theta = \sqrt{1 - \sin^2 \theta}\]
\[ = \sqrt{1 - \left( \frac{4}{5} \right)^2}\]
\[ = \frac{3}{5}\]
APPEARS IN
संबंधित प्रश्न
Find the principal and general solutions of the equation sec x = 2
Find the principal and general solutions of the equation `cot x = -sqrt3`
Find the general solution for each of the following equations sec2 2x = 1– tan 2x
If \[T_n = \sin^n x + \cos^n x\], prove that \[\frac{T_3 - T_5}{T_1} = \frac{T_5 - T_7}{T_3}\]
Prove that:
Prove that:
\[\frac{\cos (2\pi + x) cosec (2\pi + x) \tan (\pi/2 + x)}{\sec(\pi/2 + x)\cos x \cot(\pi + x)} = 1\]
Prove that
Prove that
Prove that:
\[\sec\left( \frac{3\pi}{2} - x \right)\sec\left( x - \frac{5\pi}{2} \right) + \tan\left( \frac{5\pi}{2} + x \right)\tan\left( x - \frac{3\pi}{2} \right) = - 1 .\]
Find x from the following equations:
\[cosec\left( \frac{\pi}{2} + \theta \right) + x \cos \theta \cot\left( \frac{\pi}{2} + \theta \right) = \sin\left( \frac{\pi}{2} + \theta \right)\]
If \[\frac{3\pi}{4} < \alpha < \pi, \text{ then }\sqrt{2\cot \alpha + \frac{1}{\sin^2 \alpha}}\] is equal to
sin6 A + cos6 A + 3 sin2 A cos2 A =
If \[cosec x + \cot x = \frac{11}{2}\], then tan x =
The value of sin25° + sin210° + sin215° + ... + sin285° + sin290° is
If \[cosec x + \cot x = \frac{11}{2}\], then tan x =
Find the general solution of the following equation:
Find the general solution of the following equation:
Solve the following equation:
\[\sin^2 x - \cos x = \frac{1}{4}\]
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
\[5 \cos^2 x + 7 \sin^2 x - 6 = 0\]
If \[3\tan\left( x - 15^\circ \right) = \tan\left( x + 15^\circ \right)\] \[0 < x < 90^\circ\], find θ.
If a is any real number, the number of roots of \[\cot x - \tan x = a\] in the first quadrant is (are).
The general value of x satisfying the equation
\[\sqrt{3} \sin x + \cos x = \sqrt{3}\]
If \[\cot x - \tan x = \sec x\], then, x is equal to
The number of values of x in the interval [0, 5 π] satisfying the equation \[3 \sin^2 x - 7 \sin x + 2 = 0\] is
Find the principal solution and general solution of the following:
tan θ = `- 1/sqrt(3)`
Solve the following equations:
sin 5x − sin x = cos 3
Solve the following equations:
sin θ + cos θ = `sqrt(2)`
Solve the following equations:
cot θ + cosec θ = `sqrt(3)`
Solve the following equations:
`tan theta + tan (theta + pi/3) + tan (theta + (2pi)/3) = sqrt(3)`
Solve the following equations:
cos 2θ = `(sqrt(5) + 1)/4`
If a cosθ + b sinθ = m and a sinθ - b cosθ = n, then show that a2 + b2 = m2 + n2
If 2sin2θ = 3cosθ, where 0 ≤ θ ≤ 2π, then find the value of θ.
