हिंदी

Which of the following is incorrect?

Advertisements
Advertisements

प्रश्न

Which of the following is incorrect?

विकल्प

  • \[\sin x = - \frac{1}{5}\]

     

  • cos x = 1

  • \[\sec x = \frac{1}{2}\]

     

  • tan x = 20

MCQ
Advertisements

उत्तर

`bb(sec x = 1/2)`

Explanation:

\[\sin x = - \frac{1}{5}\] is correct as \[- 1 \leq \sin x \leq 1\]

cos x = 1 is correct as cos x = 1 is correct as

\[\sec x = \frac{1}{2}\] is not correct as \[\sec x \in ( - \infty , - 1] \cup [1, \infty )\]
tan x = 20 is correct as tan x can take any real value.
Hence, the correct answer is option \[\sec x = \frac{1}{2}\].
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Trigonometric Functions - Exercise 5.5 [पृष्ठ ४३]

APPEARS IN

आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 5 Trigonometric Functions
Exercise 5.5 | Q 25 | पृष्ठ ४३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the general solution of the equation sin 2x + cos x = 0


If \[\sin x = \frac{a^2 - b^2}{a^2 + b^2}\], then the values of tan x, sec x and cosec x


Prove that: tan (−225°) cot (−405°) −tan (−765°) cot (675°) = 0


Prove that:
\[\sec\left( \frac{3\pi}{2} - x \right)\sec\left( x - \frac{5\pi}{2} \right) + \tan\left( \frac{5\pi}{2} + x \right)\tan\left( x - \frac{3\pi}{2} \right) = - 1 .\]


In a ∆ABC, prove that:

\[\cos\left( \frac{A + B}{2} \right) = \sin\frac{C}{2}\]

 


\[\sqrt{\frac{1 + \cos x}{1 - \cos x}}\] is equal to

 


If tan \[x = - \frac{1}{\sqrt{5}}\] and θ lies in the IV quadrant, then the value of cos x is

 

\[\sec^2 x = \frac{4xy}{(x + y )^2}\] is true if and only if

 


If x is an acute angle and \[\tan x = \frac{1}{\sqrt{7}}\], then the value of \[\frac{{cosec}^2 x - \sec^2 x}{{cosec}^2 x + \sec^2 x}\] is


The value of sin25° + sin210° + sin215° + ... + sin285° + sin290° is


sin2 π/18 + sin2 π/9 + sin2 7π/18 + sin2 4π/9 =


If \[f\left( x \right) = \cos^2 x + \sec^2 x\], then


Which of the following is correct?


Find the general solution of the following equation:

\[\sec x = \sqrt{2}\]

Find the general solution of the following equation:

\[\tan x = - \frac{1}{\sqrt{3}}\]

Find the general solution of the following equation:

\[\tan px = \cot qx\]

 


Solve the following equation:

\[\sin x + \sin 5x = \sin 3x\]

Solve the following equation:

\[\sqrt{3} \cos x + \sin x = 1\]


Solve the following equation:

`cosec  x = 1 + cot x`


Solve the following equation:
\[5 \cos^2 x + 7 \sin^2 x - 6 = 0\]


Solve the following equation:
3sin2x – 5 sin x cos x + 8 cos2 x = 2


If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x.


Write the values of x in [0, π] for which \[\sin 2x, \frac{1}{2}\]

 and cos 2x are in A.P.


Write the number of values of x in [0, 2π] that satisfy the equation \[\sin x - \cos x = \frac{1}{4}\].


The smallest value of x satisfying the equation

\[\sqrt{3} \left( \cot x + \tan x \right) = 4\] is 

If \[\tan px - \tan qx = 0\], then the values of θ form a series in

 


The general value of x satisfying the equation
\[\sqrt{3} \sin x + \cos x = \sqrt{3}\]


The smallest positive angle which satisfies the equation ​

\[2 \sin^2 x + \sqrt{3} \cos x + 1 = 0\] is

If \[4 \sin^2 x = 1\], then the values of x are

 


A value of x satisfying \[\cos x + \sqrt{3} \sin x = 2\] is

 

In (0, π), the number of solutions of the equation ​ \[\tan x + \tan 2x + \tan 3x = \tan x \tan 2x \tan 3x\] is 


Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°

sin4x = sin2x


Solve the following equations:
sin θ + cos θ = `sqrt(2)`


Solve the following equations:
`sin theta + sqrt(3) cos theta` = 1


Solve the following equations:
`tan theta + tan (theta + pi/3) + tan (theta + (2pi)/3) = sqrt(3)`


Solve the following equations:
2cos 2x – 7 cos x + 3 = 0


Choose the correct alternative:
If cos pθ + cos qθ = 0 and if p ≠ q, then θ is equal to (n is any integer)


Choose the correct alternative:
If f(θ) = |sin θ| + |cos θ| , θ ∈ R, then f(θ) is in the interval


Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×