Advertisements
Advertisements
प्रश्न
Which of the following is incorrect?
पर्याय
- \[\sin x = - \frac{1}{5}\]
cos x = 1
- \[\sec x = \frac{1}{2}\]
tan x = 20
Advertisements
उत्तर
`bb(sec x = 1/2)`
Explanation:
\[\sin x = - \frac{1}{5}\] is correct as \[- 1 \leq \sin x \leq 1\]
cos x = 1 is correct as cos x = 1 is correct as
APPEARS IN
संबंधित प्रश्न
Find the general solution of the equation sin x + sin 3x + sin 5x = 0
If \[x = \frac{2 \sin x}{1 + \cos x + \sin x}\], then prove that
If \[\cot x \left( 1 + \sin x \right) = 4 m \text{ and }\cot x \left( 1 - \sin x \right) = 4 n,\] \[\left( m^2 + n^2 \right)^2 = mn\]
If \[T_n = \sin^n x + \cos^n x\], prove that \[6 T_{10} - 15 T_8 + 10 T_6 - 1 = 0\]
Prove that: tan (−225°) cot (−405°) −tan (−765°) cot (675°) = 0
Prove that
Prove that
If tan x + sec x = \[\sqrt{3}\], 0 < x < π, then x is equal to
If tan \[x = - \frac{1}{\sqrt{5}}\] and θ lies in the IV quadrant, then the value of cos x is
If \[\frac{3\pi}{4} < \alpha < \pi, \text{ then }\sqrt{2\cot \alpha + \frac{1}{\sin^2 \alpha}}\] is equal to
If x is an acute angle and \[\tan x = \frac{1}{\sqrt{7}}\], then the value of \[\frac{{cosec}^2 x - \sec^2 x}{{cosec}^2 x + \sec^2 x}\] is
The value of sin25° + sin210° + sin215° + ... + sin285° + sin290° is
If A lies in second quadrant 3tan A + 4 = 0, then the value of 2cot A − 5cosA + sin A is equal to
Find the general solution of the following equation:
Find the general solution of the following equation:
Find the general solution of the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
Solve the following equation:
\[2 \sin^2 x = 3\cos x, 0 \leq x \leq 2\pi\]
Solve the following equation:
\[\sin x - 3\sin2x + \sin3x = \cos x - 3\cos2x + \cos3x\]
Solve the following equation:
3sin2x – 5 sin x cos x + 8 cos2 x = 2
Write the general solutions of tan2 2x = 1.
Write the number of points of intersection of the curves
If \[3\tan\left( x - 15^\circ \right) = \tan\left( x + 15^\circ \right)\] \[0 < x < 90^\circ\], find θ.
A solution of the equation \[\cos^2 x + \sin x + 1 = 0\], lies in the interval
A value of x satisfying \[\cos x + \sqrt{3} \sin x = 2\] is
If \[e^{\sin x} - e^{- \sin x} - 4 = 0\], then x =
General solution of \[\tan 5 x = \cot 2 x\] is
The solution of the equation \[\cos^2 x + \sin x + 1 = 0\] lies in the interval
Solve the following equations for which solution lies in the interval 0° ≤ θ < 360°
cos 2x = 1 − 3 sin x
Solve the following equations:
`tan theta + tan (theta + pi/3) + tan (theta + (2pi)/3) = sqrt(3)`
Solve the following equations:
cos 2θ = `(sqrt(5) + 1)/4`
Choose the correct alternative:
If f(θ) = |sin θ| + |cos θ| , θ ∈ R, then f(θ) is in the interval
Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π.
Find the general solution of the equation sinx – 3sin2x + sin3x = cosx – 3cos2x + cos3x
