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प्रश्न
Find the principal solution and general solution of the following:
cot θ = `sqrt(3)`
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उत्तर
`1/cot theta = 1/sqrt(3)`
⇒ tan θ = `1/sqrt(3)`
The principal value of tan θ lies in `(- pi/2, pi/2)`
Since tan θ = `1/sqrt(3) > 0`
The principal value of tan θ lies in the I quadrant.
tan θ = `1/sqrt(3)`
= `tan (pi/6)`
θ = `pi/6` is the principal solution
The general solution of tan θ is
θ = `"n"pi + pi/6`, n ∈ Z
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