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Find the principal solution and general solution of the following:cot θ = 3

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प्रश्न

Find the principal solution and general solution of the following:
cot θ = `sqrt(3)`

योग
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उत्तर

`1/cot theta = 1/sqrt(3)`

⇒ tan θ = `1/sqrt(3)`

The principal value of tan θ lies in `(- pi/2, pi/2)`

Since tan θ = `1/sqrt(3) > 0`

The principal value of tan θ lies in the I quadrant.

tan θ = `1/sqrt(3)`

= `tan (pi/6)`

θ = `pi/6` is the principal solution

The general solution of tan θ is

θ = `"n"pi + pi/6`, n ∈ Z

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - Exercise 3.8 [पृष्ठ १३३]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 3 Trigonometry
Exercise 3.8 | Q 1. (ii) | पृष्ठ १३३

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