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प्रश्न
Find the general solution of the following equation:
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उत्तर
We have:
⇒ \[\cos3x = \cos \left( \frac{\pi}{2} - 2x \right)\]
⇒ \[3x = 2n\pi \pm \left( \frac{\pi}{2} - 2x \right), n \in Z\]
On taking positive sign, we have:
\[3x = 2n\pi + \left( \frac{\pi}{2} - 2x \right)\]
⇒ \[5x = 2n\pi + \frac{\pi}{2}\]
⇒ \[x = \frac{2n\pi}{5} + \frac{\pi}{10}\]
⇒ \[x = (4n + 1)\frac{\pi}{10}\]
Now, on taking negative sign, we have:
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