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Find the value of (1+π8)(1+cos 3π8)(1+cos 5π8)(1+cos 7π8) - Mathematics

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प्रश्न

Find the value of `(1 + cos  pi/8)(1 + cos  (3pi)/8)(1 + cos  (5pi)/8)(1 + cos  (7pi)/8)`

योग
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उत्तर

Write `(1 + cos  pi/8)(1 + cos  (3pi)/8)(1 + cos  (5pi)/8)(1 + cos  (7pi)/8)`

= `(1 + cos  pi/8)(1 + cos  (3pi)/8)(1 + cos  (pi - (3pi)/8))(1 + cos(pi - pi/8))`

= `(1 - cos^2  pi/8)(1 - cos^2  (3pi)/8)` 

= `sin^2  pi/8 sin^2  (3pi)/8`

= `1/4 (1 - cos  pi/4)(1 - cos  (3pi)/4)`   

= `1/4 (1 - cos  pi/4)(1 + cos  pi/4)`

= `1/4 (1 - cos^2  pi/4)`

= `1/4(1 - 1/2)`

= `1/8`

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Sine and Cosine Formulae and Their Applications
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अध्याय 3: Trigonometric Functions - Solved Examples [पृष्ठ ४३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Solved Examples | Q 9 | पृष्ठ ४३

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