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In δ a B C , I F ∠ B = 60 ° , Prove that ( a + B + C ) ( a − B + C ) = 3 C a

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प्रश्न

In \[∆ ABC, if \angle B = 60°,\]  prove that \[\left( a + b + c \right) \left( a - b + c \right) = 3ca\]

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उत्तर

\[\text{ Given }, \angle B = 60°\] 

\[\text{ We know that }, \cos B = \frac{a^2 + c^2 - b^2}{2ac}\]

\[ \Rightarrow \cos60° = \frac{a^2 + c^2 - b^2}{2ac}\] 

\[ \Rightarrow \frac{1}{2} = \frac{a^2 + c^2 - b^2}{2ac} \left( \because \cos60° = \frac{1}{2} \right)\] 

\[ \Rightarrow ac = a^2 + c^2 - b^2 \]

\[ \Rightarrow 3ac - 2ac = a^2 + c^2 - b^2 \]

\[ \Rightarrow 3ac = a^2 + c^2 - b^2 + 2ac\]

\[ \Rightarrow 3ac = a^2 + c^2 + 2ac - b^2 \]

\[ \Rightarrow 3ac = \left( a + c \right)^2 - b^2 \]

\[ \Rightarrow 3ac = \left( a + c + b \right)\left( a + c - b \right)\]

\[ \Rightarrow 3ac = \left( a + b + c \right)\left( a - b + c \right)\]

Hence proved. 

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Sine and Cosine Formulae and Their Applications
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Sine and cosine formulae and their applications - Exercise 10.2 [पृष्ठ २५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 10 Sine and cosine formulae and their applications
Exercise 10.2 | Q 16 | पृष्ठ २५

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