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Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π

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Question

Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π.

Sum
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Solution

Here, 2 tan2x + sec2x = 2

Which gives tan x = `+- 1/sqrt(3)`

If we take tan x = `1/sqrt(3)`

Then x = `pi/6` or `(7pi)/6`  

Again, if we take tan x = `(-1)/sqrt(3)`

Then x = `(5pi)/6` or `(11pi)/6`

Therefore, the possible solutions to the above equations are

x = `pi/6, (5pi)/6, (7pi)/6` and `(11pi)/6` where 0 ≤ x ≤ 2π.

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Chapter 3: Trigonometric Functions - Solved Examples [Page 42]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 3 Trigonometric Functions
Solved Examples | Q 8 | Page 42

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