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प्रश्न
Show that it is not possible for a photon to be completely absorbed by a free electron.
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उत्तर
When an electron undergoes an inelastic collision with a photon, we can apply the principle of conservation of energy to this collision. So,
`pc + m_eC^2 = sqrt(p^2C^2 + m_e^2C^4) ....(1)`
Here, h = Planck's constant
c = the speed of light
me = rest mass of electron
pc = energy of the photon
Squaring on both side of equation (1),
`(pc + m_eC^2)^2 = p^2C^2 + m_e^2C^4`
`⇒ p^2C^2 + m_e^2C^4 + 2(pc)(m_eC^2) = p^2C^2 + m_e^2C^4`
`⇒ 2(pc)(m_eC^2) = 0 or pc = 0 ("as" 'm' and 'c' "are non zero")`
This gives vanishing energy of photon which is not possible.
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संबंधित प्रश्न
The following graph shows the variation of photocurrent for a photosensitive metal :

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(b) What does the point A on the horizontal axis represent?
(c) Draw this graph for three different values of frequencies of incident radiation v1, v2 and v3 (v1 > v2 > v3) for same intensity.
(d) Draw this graph for three different values of intensities of incident radiation I1, I2 and I3 (I1 > I2 > I3) having same frequency.
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The equation E = pc is valid
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An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 700 nm. Find the net energy absorbed by the atom in the process.
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
A beam of white light is incident normally on a plane surface absorbing 70% of the light and reflecting the rest. If the incident beam carries 10 W of power, find the force exerted by it on the surface.
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
A sphere of radius 1.00 cm is placed in the path of a parallel beam of light of large aperture. The intensity of the light is 0.5 W cm−2. If the sphere completely absorbs the radiation falling on it, find the force exerted by the light beam on the sphere.
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
The work function of a metal is 2.5 × 10−19 J. (a) Find the threshold frequency for photoelectric emission. (b) If the metal is exposed to a light beam of frequency 6.0 × 1014 Hz, what will be the stopping potential?
(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)
In an experiment on photoelectric effect, the stopping potential is measured for monochromatic light beams corresponding to different wavelengths. The data collected are as follows:-
Wavelength (nm): 350 400 450 500 550
Stopping potential (V): 1.45 1.00 0.66 0.38 0.16
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(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)

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(a) Which physical parameter is kept constant for the three curves?
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| The figure shows the variation of photoelectric current measured in a photocell circuit as a function of the potential difference between the plates of the photocell when light beams A, B, C and D of different wavelengths are incident on the photocell. Examine the given figure and answer the following questions: |

- Which light beam has the highest frequency and why?
- Which light beam has the longest wavelength and why?
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(Given, hc = 1242 eV nm)




