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Show that It is Not Possible for a Photon to Be Completely Absorbed by a Free Electron.

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प्रश्न

Show that it is not possible for a photon to be completely absorbed by a free electron.

योग
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उत्तर

When an electron undergoes an inelastic collision with a photon, we can apply the principle of conservation of energy to this collision. So,

`pc + m_eC^2 = sqrt(p^2C^2 + m_e^2C^4)    ....(1)`

Here, h = Planck's constant
        c = the speed of light
       me = rest mass of electron
       pc = energy of the photon

Squaring on both side of equation (1),

`(pc + m_eC^2)^2 = p^2C^2 + m_e^2C^4`

`⇒ p^2C^2 + m_e^2C^4 + 2(pc)(m_eC^2) = p^2C^2 + m_e^2C^4`

`⇒ 2(pc)(m_eC^2) = 0 or pc = 0  ("as" 'm' and 'c' "are non zero")`

This gives vanishing energy of photon which is not possible.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 42: Photoelectric Effect and Wave-Particle Duality - Exercises [पृष्ठ ३६५]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 42 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 12 | पृष्ठ ३६५

संबंधित प्रश्न

Ultraviolet light of wavelength 2271 Å from a 100 W mercury source irradiates a photo-cell made of molybdenum metal. If the stopping potential is −1.3 V, estimate the work function of the metal. How would the photo-cell respond to a high intensity (∼105 W m−2) red light of wavelength 6328 Å produced by a He-Ne laser?


Let nr and nb be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time.


The work function of a metal is hv0. Light of frequency v falls on this metal. Photoelectric effect will take place only if


When the intensity of a light source in increased,
(a) the number of photons emitted by the source in unit time increases
(b) the total energy of the photons emitted per unit time increases
(c) more energetic photons are emitted
(d) faster photons are emitted


The electric field associated with a light wave is given by `E = E_0 sin [(1.57 xx 10^7  "m"^-1)(x - ct)]`. Find the stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function 1.9 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


The figure is the plot of stopping potential versus the frequency of the light used in an experiment on photoelectric effect. Find (a) the ratio h/e and (b) the work function.


In the case of photoelectric effect experiment, explain the following facts, giving reasons.
The photoelectric current increases with increase of intensity of incident light.


Do all the electrons that absorb a photon come out as photoelectrons?


Two monochromatic beams A and B of equal intensity I, hit a screen. The number of photons hitting the screen by beam A is twice that by beam B. Then what inference can you make about their frequencies?


Consider a 20 W bulb emitting light of wavelength 5000 Å and shining on a metal surface kept at a distance 2 m. Assume that the metal surface has work function of 2 eV and that each atom on the metal surface can be treated as a circular disk of radius 1.5 Å.

  1. Estimate no. of photons emitted by the bulb per second. [Assume no other losses]
  2. Will there be photoelectric emission?
  3. How much time would be required by the atomic disk to receive energy equal to work function (2 eV)?
  4. How many photons would atomic disk receive within time duration calculated in (iii) above?
  5. Can you explain how photoelectric effect was observed instantaneously?

The graph shows the variation of photocurrent for a photosensitive metal

  1. What does X and A on the horizontal axis represent?
  2. Draw this graph for three different values of frequencies of incident radiation ʋ1, ʋ2 and ʋ3 (ʋ3 > ʋ2 > ʋ1) for the same intensity.
  3. Draw this graph for three different values of intensities of incident radiation I1, I2 and I3 (I3 > I2 > I1) having the same frequency.

Why it is the frequency and not the intensity of the light source that determines whether the emission of photoelectrons will occur or not? Explain.


If photons of ultraviolet light of energy 12 eV are incident on a metal surface of work function of 4 eV, then the stopping potential (in eV) will be :


A metallic plate exposed to white light emits electrons. For which of the following colours of light, the stopping potential will be maximum?


What is studied when light falls on a metal surface?


Which part is the photosensitive metal plate?


What changes the polarity between the plates?


How does collector plate A help measure current?


Between which two parts is a potential difference applied?


What is noted when light intensity is changed?


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