हिंदी

Define the Term 'Intensity of Radiation' in Terms of Photon Picture of Light. - Physics

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प्रश्न

Define the term 'intensity of radiation' in terms of photon picture of light.

Define intensity of radiation on the basis of photon picture of light.

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उत्तर १

The intensity of radiation is defined as the energy associated with photons emitted from a unit surface area in unit time

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उत्तर २

Intensity of radiation is defined as the number of photons falling per unit area in unit time. 

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Experimental Study of Photoelectric Effect
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2014-2015 (March) All India Set 3

संबंधित प्रश्न

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?


Is it always true that for two sources of equal intensity, the number of photons emitted in a given time are equal?


Light of wavelength λ falls on a metal with work-function hc/λ0. Photoelectric effect will take place only if


If the wavelength of light in an experiment on photoelectric effect is doubled,
(a) photoelectric emission will not take place
(b) photoelectric emission may or may not take place
(c) the stopping potential will increase
(d) the stopping potential will decrease


A sphere of radius 1.00 cm is placed in the path of a parallel beam of light of large aperture. The intensity of the light is 0.5 W cm−2. If the sphere completely absorbs the radiation falling on it, Show that the force on the sphere due to the light falling on it is the same even if the sphere is not perfectly absorbing.


The electric field associated with a light wave is given by `E = E_0 sin [(1.57 xx 10^7  "m"^-1)(x - ct)]`. Find the stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function 1.9 eV.

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


Explain how does (i) photoelectric current and (ii) kinetic energy of the photoelectrons emitted in a photocell vary if the frequency of incident radiation is doubled, but keeping the intensity same?

Show the graphical variation in the above two cases.


In photoelectric effect the photo current ______.


Why it is the frequency and not the intensity of the light source that determines whether the emission of photoelectrons will occur or not? Explain.


If photons of ultraviolet light of energy 12 eV are incident on a metal surface of work function of 4 eV, then the stopping potential (in eV) will be :


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