Advertisements
Advertisements
प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Advertisements
उत्तर
`5/sqrt 7`
`= 5/sqrt 7 xx sqrt 7/ sqrt 7`
`= (5 sqrt 7)/(sqrt 7)^2 `
`= (5 sqrt 7)/7`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt14`
Write the lowest rationalising factor of 5√2.
Write the lowest rationalising factor of : √24
Write the lowest rationalising factor of : 7 - √7
Write the lowest rationalising factor of : √13 + 3
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : y2
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn
If x = 2√3 + 2√2, find: `(x + 1/x)`
If x = 1 - √2, find the value of `( x - 1/x )^3`
Show that :
`1/[ 3 - 2√2] - 1/[ 2√2 - √7 ] + 1/[ √7 - √6 ] - 1/[ √6 - √5 ] + 1/[√5 - 2] = 5`
Rationalise the denominator `(3sqrt(5))/sqrt(6)`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
Rationalise the denominator and simplify `(5sqrt(3) + sqrt(2))/(sqrt(3) + sqrt(2))`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
Given `sqrt(2)` = 1.414, find the value of `(8 - 5sqrt(2))/(3 - 2sqrt(2))` (to 3 places of decimals).
