Advertisements
Advertisements
प्रश्न
Find the values of 'a' and 'b' in each of the following:
`( sqrt7 - 2 )/( sqrt7 + 2 ) = asqrt7 + b`
Advertisements
उत्तर
`( sqrt7 - 2 )/( sqrt7 + 2 ) = asqrt7 + b`
`[( sqrt7 - 2 )^2]/[ (sqrt7)^2 - (2)^2] = asqrt7 + b`
`[ 7 + 4 - 4sqrt7 ]/[ 7 - 4 ] = asqrt7 + b`
`[ 11 - 4sqrt7 ]/[ 3 ] = asqrt7 + b`
`a = -4/3, b = 11/3`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Rationalize the denominator.
`11 / sqrt 3`
Write the lowest rationalising factor of √5 - 3.
Write the lowest rationalising factor of : √18 - √50
Write the lowest rationalising factor of : √5 - √2
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn
If x = 1 - √2, find the value of `( x - 1/x )^3`
If `[ 2 + sqrt5 ]/[ 2 - sqrt5] = x and [2 - sqrt5 ]/[ 2 + sqrt5] = y`; find the value of x2 - y2.
Find the value of a and b if `(sqrt(7) - 2)/(sqrt(7) + 2) = asqrt(7) + b`.
