Advertisements
Advertisements
प्रश्न
Write the lowest rationalising factor of : √5 - √2
योग
Advertisements
उत्तर
√5 - √2
( √5 - √2 )( √5 + √2 ) = ( √5 )2 - ( √2 )2 = 3
Therefore lowest rationalizing factor is √5 + √2
shaalaa.com
Rationalisation of Surds
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Write the lowest rationalising factor of 5√2.
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x2
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n2
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
If x = 2√3 + 2√2, find: `(x + 1/x)`
Evaluate: `( 4 - √5 )/( 4 + √5 ) + ( 4 + √5 )/( 4 - √5 )`
If √2 = 1.4 and √3 = 1.7, find the value of : `1/(3 + 2√2)`
Find the value of a and b if `(sqrt(7) - 2)/(sqrt(7) + 2) = asqrt(7) + b`.
