Advertisements
Advertisements
प्रश्न
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
Advertisements
उत्तर
`sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2) = sqrt(5)(1/(sqrt(6) + 2) - 1/(sqrt(6) - 2))`
= `sqrt(5)[(sqrt(6) - 2 - (sqrt(6) + 2))/((sqrt(6) + 2)(sqrt(6) - 2))]`
= `sqrt(5)[(sqrt(6) - 2 - sqrt(6) - 2)/((sqrt(6))^2 - 2^2)]`
= `sqrt(5)((-4)/(6 - 4))`
= `sqrt(5)((-4)/2)`
= `sqrt(5) xx -2`
= `-2 sqrt(5)`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`6/(9sqrt 3)`
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`sqrt 32`
Write the simplest form of rationalising factor for the given surd.
`4 sqrt 11`
Write the lowest rationalising factor of : √18 - √50
Write the lowest rationalising factor of 15 – 3√2.
Find the values of 'a' and 'b' in each of the following:
`[5 + 3sqrt2]/[ 5 - 3sqrt2] = a + bsqrt2`
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
Rationalise the denominator `sqrt(75)/sqrt(18)`
If x = `sqrt(5) + 2`, then find the value of `x^2 + 1/x^2`
