Advertisements
Advertisements
प्रश्न
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
Advertisements
उत्तर
`sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2) = sqrt(5)(1/(sqrt(6) + 2) - 1/(sqrt(6) - 2))`
= `sqrt(5)[(sqrt(6) - 2 - (sqrt(6) + 2))/((sqrt(6) + 2)(sqrt(6) - 2))]`
= `sqrt(5)[(sqrt(6) - 2 - sqrt(6) - 2)/((sqrt(6))^2 - 2^2)]`
= `sqrt(5)((-4)/(6 - 4))`
= `sqrt(5)((-4)/2)`
= `sqrt(5) xx -2`
= `-2 sqrt(5)`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Write the lowest rationalising factor of : 7 - √7
Write the lowest rationalising factor of : √13 + 3
Write the lowest rationalising factor of : 3√2 + 2√3
If x = 2√3 + 2√2, find: `(x + 1/x)`
If x = 1 - √2, find the value of `( x - 1/x )^3`
If x = 5 - 2√6, find `x^2 + 1/x^2`
If `[ 2 + sqrt5 ]/[ 2 - sqrt5] = x and [2 - sqrt5 ]/[ 2 + sqrt5] = y`; find the value of x2 - y2.
Rationalise the denominator `5/(3sqrt(5))`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
