Advertisements
Advertisements
प्रश्न
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
Advertisements
उत्तर
`1/x = 1/[2sqrt3 + 2sqrt2] xx [2sqrt3 - 2sqrt2]/[2sqrt3 - 2sqrt2]`
= `[2sqrt3 - 2sqrt2]/[(2sqrt3)^2 - (2sqrt2)^2]`
= `[2sqrt3 - 2sqrt2]/(12 - 8)`
= `[cancel(2)^1(sqrt3 - sqrt2)]/cancel(4)_2`
= `(sqrt3 - sqrt2)/2`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`sqrt 27`
Write the lowest rationalising factor of √5 - 3.
Write the lowest rationalising factor of : √5 - √2
Write the lowest rationalising factor of 15 – 3√2.
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If x = 1 - √2, find the value of `( x - 1/x )^3`
If `[ 2 + sqrt5 ]/[ 2 - sqrt5] = x and [2 - sqrt5 ]/[ 2 + sqrt5] = y`; find the value of x2 - y2.
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
