Advertisements
Advertisements
प्रश्न
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
Advertisements
उत्तर
`1/x = 1/[2sqrt3 + 2sqrt2] xx [2sqrt3 - 2sqrt2]/[2sqrt3 - 2sqrt2]`
= `[2sqrt3 - 2sqrt2]/[(2sqrt3)^2 - (2sqrt2)^2]`
= `[2sqrt3 - 2sqrt2]/(12 - 8)`
= `[cancel(2)^1(sqrt3 - sqrt2)]/cancel(4)_2`
= `(sqrt3 - sqrt2)/2`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`3 /sqrt5`
Write the simplest form of rationalising factor for the given surd.
`sqrt 50`
Write the lowest rationalising factor of : √24
Find the values of 'a' and 'b' in each of the following:
`( sqrt7 - 2 )/( sqrt7 + 2 ) = asqrt7 + b`
Find the values of 'a' and 'b' in each of the following:
`[5 + 3sqrt2]/[ 5 - 3sqrt2] = a + bsqrt2`
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : y2
If x = 1 - √2, find the value of `( x - 1/x )^3`
If √2 = 1.4 and √3 = 1.7, find the value of : `1/(3 + 2√2)`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
Given `sqrt(2)` = 1.414, find the value of `(8 - 5sqrt(2))/(3 - 2sqrt(2))` (to 3 places of decimals).
