Advertisements
Advertisements
Question
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
Advertisements
Solution
`1/x = 1/[2sqrt3 + 2sqrt2] xx [2sqrt3 - 2sqrt2]/[2sqrt3 - 2sqrt2]`
= `[2sqrt3 - 2sqrt2]/[(2sqrt3)^2 - (2sqrt2)^2]`
= `[2sqrt3 - 2sqrt2]/(12 - 8)`
= `[cancel(2)^1(sqrt3 - sqrt2)]/cancel(4)_2`
= `(sqrt3 - sqrt2)/2`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`3 sqrt 72`
Write the lowest rationalising factor of : √24
Write the lowest rationalising factor of 15 – 3√2.
Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
If √2 = 1.4 and √3 = 1.7, find the value of : `1/(√3 - √2)`
Rationalise the denominator `1/sqrt(50)`
Rationalise the denominator `(3sqrt(5))/sqrt(6)`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
Rationalise the denominator and simplify `(5sqrt(3) + sqrt(2))/(sqrt(3) + sqrt(2))`
