Advertisements
Advertisements
Question
Write the simplest form of rationalising factor for the given surd.
`sqrt 27`
Advertisements
Solution
Since , `sqrt 27 = sqrt (9 xx 3) = 3 sqrt 3`
`therefore 3sqrt3 xx sqrt3 = 3 xx 3 = 9` is a rational number.
So, `sqrt 3` is the simplest form of rationalising factor.
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`3 /sqrt5`
Rationalize the denominator.
`1/sqrt14`
Rationalize the denominator.
`5/sqrt 7`
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`3/5 sqrt 10`
Write the simplest form of rationalising factor for the given surd.
`3 sqrt 72`
Write the simplest form of rationalising factor for the given surd.
`4 sqrt 11`
Write the lowest rationalising factor of √5 - 3.
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x2
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : y2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find m2
If x = `2sqrt3 + 2sqrt2`, find: `1/x`
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
If x = 1 - √2, find the value of `( x - 1/x )^3`
Show that :
`1/[ 3 - 2√2] - 1/[ 2√2 - √7 ] + 1/[ √7 - √6 ] - 1/[ √6 - √5 ] + 1/[√5 - 2] = 5`
Rationalise the denominator `5/(3sqrt(5))`
Rationalise the denominator and simplify `(5sqrt(3) + sqrt(2))/(sqrt(3) + sqrt(2))`
