Advertisements
Advertisements
Question
If x = 2√3 + 2√2, find: `(x + 1/x)`
Advertisements
Solution
`x + 1/x = 2sqrt3 + 2sqrt2 + (√3 - √2)/2`
= `2( sqrt3 + sqrt2 ) + (sqrt3 - sqrt2)/2`
= `(4( sqrt3 + sqrt2) + (sqrt3 - sqrt2))/2`
= `[ 4sqrt3 + 4sqrt2 + sqrt3 - sqrt2 ]/2`
= `[ 5sqrt3 + 3sqrt2 ]/2`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`sqrt 50`
Write the lowest rationalising factor of 5√2.
Write the lowest rationalising factor of : √5 - √2
Write the lowest rationalising factor of : √13 + 3
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x2
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
If x = 5 - 2√6, find `x^2 + 1/x^2`
Rationalise the denominator `sqrt(75)/sqrt(18)`
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
