Rationalise the denominator 356 - Mathematics

Rationalise the denominator `(3sqrt(5))/sqrt(6)`

Sum

`(3sqrt(5))/sqrt(6) = (3sqrt(5))/sqrt(6) xx sqrt(6)/sqrt(6)`

= `(3sqrt(30))/6`

= `sqrt(30)/2`

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Rationalisation of Surds

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Chapter 2: Real Numbers - Exercise 2.7 [Page 70]

Chapter 2 Real Numbers
Exercise 2.7 | Q 1. (iv) | Page 70

Rationalize the denominator.

`5/sqrt 7`

Write the lowest rationalising factor of 5√2.

Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`

If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n²

If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn

If x = 1 - √2, find the value of `( x - 1/x )^3`

Show that :
`1/[ 3 - 2√2] - 1/[ 2√2 - √7 ] + 1/[ √7 - √6 ] - 1/[ √6 - √5 ] + 1/[√5 - 2] = 5`

If √2 = 1.4 and √3 = 1.7, find the value of : `1/(√3 - √2)`

Rationalise the denominator `1/sqrt(50)`

Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`