Rationalise the denominator 356

Rationalise the denominator `(3sqrt(5))/sqrt(6)`

योग

`(3sqrt(5))/sqrt(6) = (3sqrt(5))/sqrt(6) xx sqrt(6)/sqrt(6)`

= `(3sqrt(30))/6`

= `sqrt(30)/2`

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Rationalisation of Surds

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अध्याय 2: Real Numbers - Exercise 2.7 [पृष्ठ ७०]

अध्याय 2 Real Numbers
Exercise 2.7 | Q 1. (iv) | पृष्ठ ७०

Write the lowest rationalising factor of : 7 - √7

Write the lowest rationalising factor of : √18 - √50

Write the lowest rationalising factor of : √13 + 3

Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`

If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find :
x²

If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n²

If x = `2sqrt3 + 2sqrt2`, find: `1/x`

If x = 2√3 + 2√2, find: `(x + 1/x)`

Rationalise the denominator `sqrt(75)/sqrt(18)`

Given `sqrt(2)` = 1.414, find the value of `(8 - 5sqrt(2))/(3 - 2sqrt(2))` (to 3 places of decimals).