Advertisements
Advertisements
Question
Rationalise the denominator `1/sqrt(50)`
Advertisements
Solution
`1/sqrt(50) = 1/(sqrt(25 xx 2)`
= `1/(5sqrt(2))`
= `1/(5sqrt(2)) xx sqrt(2)/sqrt(2)`
= `sqrt(2)/(5 xx 2)`
= `sqrt(2)/10`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`11 / sqrt 3`
Write the simplest form of rationalising factor for the given surd.
`sqrt 32`
Write the lowest rationalising factor of : √5 - √2
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn
Evaluate: `( 4 - √5 )/( 4 + √5 ) + ( 4 + √5 )/( 4 - √5 )`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
Given `sqrt(2)` = 1.414, find the value of `(8 - 5sqrt(2))/(3 - 2sqrt(2))` (to 3 places of decimals).
