Advertisements
Advertisements
प्रश्न
Rationalise the denominator `1/sqrt(50)`
Advertisements
उत्तर
`1/sqrt(50) = 1/(sqrt(25 xx 2)`
= `1/(5sqrt(2))`
= `1/(5sqrt(2)) xx sqrt(2)/sqrt(2)`
= `sqrt(2)/(5 xx 2)`
= `sqrt(2)/10`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`3 /sqrt5`
Rationalize the denominator.
`11 / sqrt 3`
Write the lowest rationalising factor of 15 – 3√2.
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find m2
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find n2
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
If x = 5 - 2√6, find `x^2 + 1/x^2`
If `[ 2 + sqrt5 ]/[ 2 - sqrt5] = x and [2 - sqrt5 ]/[ 2 + sqrt5] = y`; find the value of x2 - y2.
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
