Advertisements
Advertisements
प्रश्न
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
Advertisements
उत्तर
`[ 2 + sqrt3 ]/[ 2 - sqrt3 ] xx [ 2 + sqrt3 ]/[ 2 + sqrt3] = a + bsqrt3`
= `[ (2 + sqrt3)^2 ]/[ (2)^2 - (sqrt3)^2 ] = a + bsqrt3`
= `[ 4 + 3 + 4sqrt3]/[ 4 - 3 ] = a + bsqrt3`
7 + 4√3 = a + b√3
a = 7, b = 4
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Rationalize the denominator.
`6/(9sqrt 3)`
Write the lowest rationalising factor of : √18 - √50
Write the lowest rationalising factor of : 3√2 + 2√3
Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find m2
Rationalise the denominator `5/(3sqrt(5))`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
Rationalise the denominator and simplify `(5sqrt(3) + sqrt(2))/(sqrt(3) + sqrt(2))`
Find the value of a and b if `(sqrt(7) - 2)/(sqrt(7) + 2) = asqrt(7) + b`.
