Advertisements
Advertisements
प्रश्न
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Advertisements
उत्तर
`[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ] xx [ 2√5 + 3√2 ]/[ 2√5 + 3√2 ]`
= `[( 2sqrt5 + 3sqrt2)^2]/[ (2sqrt5)^2 - (3sqrt2)^2]`
= `[ 4 xx 5 + 9 xx 2 + 12sqrt10 ]/[ 20 -18 ]`
= `[ 20 + 18 + 12sqrt10 ]/2`
= `[ 38 + 12sqrt10 ]/2`
= `[2( 19 + 6sqrt10 )]/2`
= 19 + 6√10
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Simplify:
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
Simplify by rationalising the denominator in the following.
`(5sqrt(3) - sqrt(15))/(5sqrt(3) + sqrt(15)`
Simplify the following
`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`
If `(sqrt(2.5) - sqrt(0.75))/(sqrt(2.5) + sqrt(0.75)) = "p" + "q"sqrt(30)`, find the values of p and q.
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `(7 + 4sqrt(3))`, find the values of :
`(x + (1)/x)^2`
If x = `(4 - sqrt(15))`, find the values of
`x^2 + (1)/x^2`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
