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प्रश्न
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
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उत्तर
`[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ] xx [ 2√5 + 3√2 ]/[ 2√5 + 3√2 ]`
= `[( 2sqrt5 + 3sqrt2)^2]/[ (2sqrt5)^2 - (3sqrt2)^2]`
= `[ 4 xx 5 + 9 xx 2 + 12sqrt10 ]/[ 20 -18 ]`
= `[ 20 + 18 + 12sqrt10 ]/2`
= `[ 38 + 12sqrt10 ]/2`
= `[2( 19 + 6sqrt10 )]/2`
= 19 + 6√10
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संबंधित प्रश्न
Rationalise the denominators of : `3/sqrt5`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominators of : `[ √3 + 1 ]/[ √3 - 1 ]`
Simplify by rationalising the denominator in the following.
`(1)/(5 + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`
Simplify by rationalising the denominator in the following.
`(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
Simplify the following :
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
In the following, find the values of a and b:
`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`
In the following, find the value of a and b:
`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`
