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प्रश्न
Simplify by rationalising the denominator in the following.
`(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)`
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उत्तर
`(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)`
= `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)) xx (3sqrt(5) + 2sqrt(6))/(3sqrt(5) + 2sqrt(6)`
= `(6sqrt(30) + 24 - 15 - 2sqrt(30))/((3sqrt(5))^2 - (2sqrt(6))^2`
= `(6sqrt(30) + 9 - 2sqrt(30))/(45 - 24)`
= `(4sqrt(30) + 9)/(21)`
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संबंधित प्रश्न
Rationalise the denominators of : `3/sqrt5`
Rationalise the denominators of : `[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ]`
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`(1)/(sqrt(3) + sqrt(2))`
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`(5 + sqrt(6))/(5 - sqrt(6)`
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`(sqrt(5) - 2)/(sqrt(5) + 2) - (sqrt(5) + 2)/(sqrt(5) - 2)`
Simplify the following :
`(3sqrt(2))/(sqrt(6) - sqrt(3)) - (4sqrt(3))/(sqrt(6) - sqrt(2)) + (2sqrt(3))/(sqrt(6) + 2)`
In the following, find the values of a and b:
`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`
In the following, find the values of a and b:
`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) = "a" - "b"sqrt(6)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x2 + y2
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
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